លំហាត់វិសមភាព

លំហាត់វិសមភាព
1.គេមាន a>0បង្ហាញថា​\displaystyle y= \frac{(a+1)(a+2)(a+3)(a+4)}{32a^2}\geq \sqrt{6}
2.គេមាន a+b+c=1 ដែលa,b,cជាចំនួនមិនអវិជ្ជមាន។​បង្ហាញថាP=(a+b)(b+c)(c+a)abc \leq \displaystyle \frac{8}{729}

To be continue……

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